Malacañang has declared September 10 a non-working holiday to give way for the celebration for the end of the Muslims' holy month of fasting, the Ramadan.
Presidential spokesman Edwin Lacierda said President Benigno Simeon Aquino III has signed Proclamation 26, declaring September 10 as a non-working holiday as Muslims celebrate the "Eid ul-Fitr," or the festivities for the end of Ramadan.
"Eid" is an Arabic word meaning "festivity" while "Fiṭr" means "to purify." The holiday is thus a symbol of purification after completing the fasting month.
Ramadan is the ninth month of the Islamic calendar. The Ramadan began on August 11 this year and will end on September 10.
source: yahoo.com.ph
-- - -— LBG/VVP, GMAnews.TV
Saturday, September 4, 2010
Thursday, August 12, 2010
Film showing on Monday
Good Day!
To Nat Sci 1 - Bb2 students (every mon and thu 7-8:30am, rm 233), we'll have a filmshowing on august 16, 2010 (monday) 7-8:30am n room 235, 2nd floor math-physics bldg.
Please don't be late.
See ya!
To Nat Sci 1 - Bb2 students (every mon and thu 7-8:30am, rm 233), we'll have a filmshowing on august 16, 2010 (monday) 7-8:30am n room 235, 2nd floor math-physics bldg.
Please don't be late.
See ya!
Monday, July 19, 2010
Some Questions about topics in Prelim Coverage
Question #1: how to solve Friction Force.
(This was actually an assignment)
Problem: A 400-kg bear grasping a vertical tree slides down at constant velocity. What is the friction force that acts on the bear? (Calculate it)
The first step is: understand the description of the problem/question.
2nd step: visualize it... Draw the situation... Show all the forces which are acting on the body considered ( the bear in this case )
3rd step: Since the forces are vectors, make a sign convention... In the diagram below, if the force is directed up it should have a negative (-) coefficient once involved in an equation, if downward, positive (+). (as indicated by the violet arrow).

4th step: Use the Newton's Second Law of Motion. Start the mathematical solution from the equation a = Fnet/m. (as shown)

Fnet = W - f , because f is directed up.
Why a = 0 ? Because, as stated the bear is sliding with constant velocity (which means as it slide its velocity does not vary). So the acceleration is zero.
Question #2: Is m really cancelled? (on Gravitational force on an object)

Answer: Yes. By a law of mathematics, it is cancelled. The specific, step-by-step derivation goes like this!
(This was actually an assignment)
Problem: A 400-kg bear grasping a vertical tree slides down at constant velocity. What is the friction force that acts on the bear? (Calculate it)
The first step is: understand the description of the problem/question.
2nd step: visualize it... Draw the situation... Show all the forces which are acting on the body considered ( the bear in this case )
3rd step: Since the forces are vectors, make a sign convention... In the diagram below, if the force is directed up it should have a negative (-) coefficient once involved in an equation, if downward, positive (+). (as indicated by the violet arrow).
4th step: Use the Newton's Second Law of Motion. Start the mathematical solution from the equation a = Fnet/m. (as shown)

Fnet = W - f , because f is directed up.
Why a = 0 ? Because, as stated the bear is sliding with constant velocity (which means as it slide its velocity does not vary). So the acceleration is zero.
Question #2: Is m really cancelled? (on Gravitational force on an object)

Answer: Yes. By a law of mathematics, it is cancelled. The specific, step-by-step derivation goes like this!











